| SCHOOLS → GAMES ↓ | A | B | C | D | E |
|---|---|---|---|---|---|
| FOOTBALL | 125 | 250 | 100 | 175 | 250 |
| BASKETBALL | 175 | 200 | 195 | 245 | 225 |
| CRICKET | 250 | 200 | 225 | 215 | 200 |
| TENNIS | 240 | 210 | 200 | 130 | 165 |
| BADMINTON | 75 | 125 | 55 | 45 | 100 |
Q 1) If 20 % of the students playing football from school A also play badminton then what would be the total number of students playing badminton from school A
solution : students playing football from school A = 125 then 20 % 125 = 25( 10 % 125 = 12.5 ;20 % = 25) finally, Number of students playing badminton from school A = 75 + 25 = 100
Q 2) The number of students playing basketball from school C is approximately what percent of the students playing basketball from school E ?
solution : number of students playing basketball from school C = 195 number of students playing basketball from school E = 225 Then C / E * 100 = ( 195 / 225 ) * 100 = 86.67 %
Q 3)What is the difference between the average number of students playing cricket from all the schools and the average number of students playing tennis from all other schools ?
solution : Here we need not calculate avg of cricket players and tennis players Just take difference between cricket and tennis as follows 10 (250 - 240) -10 (200 - 210 ) +25 (225 -200 ) +85 (215-130)+35 (200-165) = 145/5 = 29
Q 4) The number of students playing football from school D is what percentage of the total number of students playing all the given games in that school ?
solution : Number of students playing football from school D = 175 total number of students playing all the given games in that school = 175 + 245 + 215 +130 + 45 = 810 Then D / other = (175 / 810) * 100 = (10 % 810 = 81 ; 5 % 810 = 40. 5 ; 1 % 810 = 8.1 ) = 20 % 810 = 162 Remaining = 13 ( approx 1.5 % 810 ) Finally Answer = 21.5 %
Q 5)What is the difference between the average number of students playing all the given games from school B and the number of students playing badminton from that school ?
solution : average number of students playing all the given games from school B = (250 +200+200+210+125)/5 200 + (50+0+0+10-75)/5 = 200-3 = 197 number of students playing badminton from that school B = 125 Answer = 197 -125 = 72
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